the hypotenuse of a right triangle is 26cm. if one of the remaining two side is 10 cm long, find the length of other side?
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Let ∆ ABC be right-angled at C.
Let AB=26 cm and BC=10 cm
Then, by pythagoras' theorem,
AB^2=BC^2+AC^2
=>AC^2= (AB^2-BC^2)
=(26^2-10^2)cm^2
=(676-100)cm^2
=576 cm^2
AC=√576 cm=24 cm
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