The hypotenuse of a right triangle is 52 in. One leg of the triangle is 8 in. more than twice the length of the other. What is the perimeter of the triangle?
20 in.
26 in.
120 in.
138 in.
I need help solving this please lol
Answers
Answered by
1
Answer:
26
Step-by-step explanation:
Answered by
3
Answer:
Ans =120 cm
Step-by-step explanation:
Let hypotenuse of the right triangle be
h
=
52
in.
One leg of the right triangle be
l
1
in.
Other leg of the right triangle be
l
2
=
2
⋅
l
1
+
8
in.
We know
h
2
=
l
2
1
+
l
2
2
or
52
2
=
l
2
1
+
(
2
l
1
+
8
)
2
or
2704
=
l
2
1
+
4
l
2
1
+
32
l
1
+
64
or
5
l
2
1
+
32
l
1
−
2640
=
0
. This is a quadratic eqqution of which
a
=
5
;
b
=
32
;
c
=
−
2640
;
l
1
=
−
32
±
√
32
2
−
4
⋅
5
⋅
(
−
2640
)
2
⋅
5
or
l
1
=
20.0
or
l
1
=
−
26.4
Length can not be negative number. So
l
1
=
20
;
l
2
=
2
⋅
20
+
8
=
48
;
h
=
52
The perimeter of the triangle is
P
=
l
1
+
l
2
+
h
=
20
+
48
+
52
=
120
cm
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