Question

The hypotenuse of a right triangle is 6×1÷2 centimetres and its area is
7×1÷2square centimetres. Calculate the lengths of its perpendicular sides. using x and y​

Answer 1

Answer:

=3

=3.5

Step-by-step explanation:

6x1÷2=3

7×1÷2=3.5

x=3

y=3.5

Answer 2

answer

x=6

y=2.5

step by step explanation

Let perpendicular sides of the triangle = x and y

so (1/2)×x×y=area =7 1/2

or, xy/2=15/2 , or, xy=15

again, hypotenuse^2=x^2+y^2

or, x^2+y^2=(6 1/2)^2=(13/2)^2

we know, (a+b)^2=a^2+b^2+2ab

=(13/2)^2+2×15=169/4+30=289/4

x+y=17/2……..(1)

again, (a-b)^2=a^2+b^2–2ab

=(13/2)^2–2×15=169/4–30=49/4

x-y=7/2 ………(2)

(1)+(2), → 2x=17/2+7/2=24/2=12

x=12/2=6 cm

(1)-(2) , → 2y=17/2–7/2=10/2=5

y=5/2=2.5 cm

two sides are 2.5cm and 6 cm