Question

The hypotenuse of a right triangle is 6 m more than twice the shortest side.if the third side is 2 m less than the hypotenuse find the sides of the triangle

Answer 1

let base be x
h= 6+2x, p=2-(6+2x)
h^2=p^2+b^2
(6+2x)^2={2-(6+2x)}^2+x^2
36+4x^2+24x=16+4x^2+16x+x^2
x^2-8x-20
x^2-(10-2)x-20
x^2-10x+2x-20
x=10, x=-2
h=26or2
p=-24or0
b=10or-2

Answer 2

$\huge {\green{\underline{ \overline{\red{ \mid{ \bold { \star{ \blue{ solu}{\mathbb{Tion}}{ \blue{ \star{\red{\mid}}}}}}}}}}}}$

Hope it helps............