The hypotenuse of a right triangle is 6 m more than twice the shortest side. If the third
side is 2 m less than the hypotenuse, find the sides of the triangle
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Answer:
let length of shortest side=x
Hyp.=(2x+6)m
third side=(2x+6-2)m=(2x+4)m
By pythagoras.
(2x+6)²=x²+(2x+4)²
x²-8x-20=0
x²-10x-2x-20=0
(x-10)(x+2)=0
x=10 or x=-2
sides of triangle can't be negative
so,x=10
length of shortest side=10m
length of hypotenuse=2x+6=2×10+6=26m
length of third side=2x+4=2×10+4=24m
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