Question

the hypotenuse of a right triangle is 65cm and it's perpendicular distance is 25cm, find the length of its base.

Answer 1

H² = P²+B²
65²=25² + B²
B= √65²-25²
B=√3600
B=60cm

Answer 2

hey there......

here is ur answer......

<> first let's learn the formula for the pythogarous theorm.....

<> it is

<>
${a}^{2} + {b}^{2} = {c}^{2}$

where A is the base

B is the perpendicular distance

C is hypotenuse

if we substitute we get

${a}^{2} + {25}^{2} = {65}^{2}$

$a = \sqrt{ {65}^{2} - {25}^{2} }$

$a = \sqrt{4225 - 625}$

$a = \sqrt{3600}$

$a = 60cm$

thank u hope this helps u

have a nice day