The hypotenuse of isosceles right triangle is 10 cm find its area by heron's formula and pythagoras property
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Step-by-step explanation:
Given a right angled isosceles triangle with a hypotenuse of 10 what is it’s area?
From Pythagoras: h*h = a*a+b*b
As the triangle is isosceles, the non-hypotenuse sides have the same length.
So: h*h = 2*a*a
=> a = root(h*h/2)
The area of the triangle is base * height / 2
So: area = a*a/2
=> root(h*h/2)*root(h*h/2)/2
=> h*h/4
=> 10 * 10 / 4
=> 25 square cm
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