Question

The hypotenuse of right angled triangle is 3 cm more than twice the base and third side is 1 cm less than the hypotenuse find the lengths ​

Answer 1

Step-by-step explanation:

h=3+2b

b=h-3/2 --------1

h=p+1

h-1=p --------2

h^{2}h

2

=p^{2}p

2

+b^{2}b

2

h^{2}h

2

= (h-1)^{2}(h−1)

2

+ (h-3/2)^{2}(h−3/2)

2

h^{2}h

2

=h^{2}h

2

- 2h +1 + h^{2}h

2

- 3h + 9/4

h^{2}h

2

- h^{2}h

2

- h^{2}h

2

= -2h - 3h +1 +9/4

- h^{2}h

2

= -5h + 11/4

h^{2}h

2

= 5h - 11/4

h = \sqrt{5h-11/4}

5h−11/4

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