The i p 1 , i p 2 , i p 3 and i p 4 of an element a are 6.0 , 10.0 , 16.0 and 45.0 e v respectively. The molecular weight of the oxide of the element a is (x is atomic weight)
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Answer: Since 4th I.P is very very high , so it could be Group13 element , so assume it be Al, then Al forms (Al2O3)
So answer is 2x+48
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