Math, asked by jimmygta5test, 8 months ago

The Identity $\sqrt{sec^{2}x+cosec^{2}x } =$

Answers

Answered by aryan073

Answer:

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Step-by-step explanation:

$\sqrt{ { \sec( \alpha ) }^{2} + { \cosec( \alpha ) }^{2} } = \sqrt{1} = 1 \: ok \: friend$

Answered by Anonymous

HERE IS UR ANSWER DEAR,

$= \sqrt{ {sec}^{2} x + {cosec}^{2}x }$

sec²+cosec²= 1=1²

$= \sqrt{ {1}^{2} }$

$= 1$

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