Question

the
if the point (2k - 3 K+2) lies
graph of
the equation 2x + 3y +15=0. Find the value of R.​

Answer 1

Step-by-step explanation:

from the above question ,

X = 2k-3 , y = k+2

putting the valu of X and y in equation

2x+3y+15 =0

2(2k-3)+3(k+2)+15=0

4k-6+3k+6+15=0

7k+15 = 0

7k = -15

k = -15/7

Answer 2

Step-by-step explanation:

Correct Question:-

If (2k-3,k+2) lies graph of the equation 2x+3y+15=0 Find the value of k.

Solution:-

• Put the point on the equation

$\\ \tt{:}\Rrightarrow 2x + 3y + 15 = 0 \\ \\ \tt{:}\Rrightarrow 2(2k - 3) + 3(k + 2) + 15 = 0 \\ \\ \tt{:}\Rrightarrow 4k - 6 + 3k + 6 + 15 = 0 \\ \\ \tt{:}\Rrightarrow 4k + 3k - 6 + 6 + 15 = 0 \\ \\ \tt{:}\Rrightarrow 7k + 15 = 0 \\ \\ \tt{:}\Rrightarrow 7k = - 15 \\ \\ \tt{:}\Rrightarrow \boxed{ \bf k = \frac{ - 15}{7} }$