Physics, asked by solankisamanta8, 1 month ago

The illustration in figure below shows a uniform metre rule weighing 30 N pivoted on a wedge placed under the 40 cm mark and carrying a weight of 70 N hanging from the 10. cm mark. The ruler is balanced horizontally by a weight Whanging from the 100 cm mark. Calculate the value of the weight W.​

Answers

Answered by janvipandita672
0

Answer:

125 g

from Equilibrium,

clockwise moment=anticlockwise moment

W×15=75×g×25

m×g×15=75×g×25

∴=

15

75×25

=125g

solution

Answered by kinggamer7698
0

Answer:

mjrstddgddytrgrx5dgtcedcdtrdrbtbrd

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