Question

the image formed by a concave mirror is half the size of object .If object is placed at 10cm from the mirror,where is the image formed?

Answer 1

The image will formed at distance 5 cm

Explanation:

Given the mirror is concave.

Object distance, u = -10 cm.

The image size of the object = half of the size of the object.

The magnification is given as

$m=-\frac{v}{u}$.

Here, v is image distance.

Also,

$m=\frac{H}{h}$.

Here, H is image size of the object(image height) and h is the size of the object (height of the object).

So,

$m=\frac{\frac{1}{2}h }{h}$

$m=\frac{1}{2}$.

Therefore, to calculate image distance use

$m=\frac{1}{2} =-\frac{v}{-10cm}$

v = 5 cm.

Thus, the image will formed at distance 5 cm.

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Answer 2

Answer:

The image will form at the distance of 5cm.

Explanation:

Given: Concave mirror

u= -10cm                             (u = distance of object from the mirror)

h= 2H                                  (h = height of object)

                                           (H = height of image formed)

To find: Image distance (v)

Solution:

We know,

m= H/h

Now,

m = H ÷ 2h                    { h=2H }

m = 1/2

Also;

m = -v/u

where,

m = magnificient

v = distance of image formed

now,

1/2 = -v/-10

1/2 =v/10

v =5cm

So, the image will form at the distance of 5cm.

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