Question

the image formed by a convex lens of an object placed in front of it at 10 cm is virtual erect and twice in size of the object what will be the position of the image formed and what will be the new position of the image and its magnification if the object is shifted at 20cm in front of the lens​

Answer 1

Answer:

Explanation:

Given:u=−10cm f=20cm (convex lens)

To find: v and image's nature.

Solution: From lens formula

1/v - 1/u= 1/f

1/v + 1/10= 1/20

1/v= -1/20

v=−20cm

And magnification = v/u =2

Hence image formed is virtual, erect and magnified two times.