Science, asked by shambhavi12102005121, 11 months ago

The image formed by concave mirror is real, inverted and of the same size as that of the object. The position of the object should be-​

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Answered by abhimalviya121
9

Answer:

The Image Formed by a Concave Mirror is Real, Inverted and of the Same Size as the Object. the Position of the Object Must Then Be: (A) at the Focus (B) Between the Centre of Curvature and Focus (C) at the Centre of Curvature (D) Beyond the Centre of Curvature Concept: Mirror Formula and Magnificent

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Answered by Mysteryboy01
4

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<marquee behaviour-move><font color="meganta"><h1>Answer</h1></marquee>

If the image formed by a concave mirror is real, inverted and of the same size as object then the position of the object must be at the center of curvature.

<!DOCTYPE html> <html> <svg width="100%" height="300px">\ \textless \ br /\ \textgreater \ <g id="R1" transform="translate(250 250)"> \ \textless \ br /\ \textgreater \ <ellipse rx="100" ry="0" opacity=".3">\ \textless \ br /\ \textgreater \ <animateTransform attributeName="transform" type="rotate" dur="7s" from="0" to="360" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="cx" dur="8s" values="-20; 220; -20" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="ry" dur="3s" values="10; 60; 10" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ </ellipse>\ \textless \ br /\ \textgreater \ </g><use xlink:href="#R1" transform="rotate(72 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(144 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(216 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(288 390 150)" />\ \textless \ br /\ \textgreater \ </svg></body></html>

<marquee behaviour-move><font color="meganta"><h1>INCreDibLE </h1></marquee>

<marquee> <font color ="green"><h1>✌️♥️ Hope it's helps u ♥️✌️</marquee>

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