Science, asked by shambhavi12102005121, 6 months ago

The image formed by concave mirror is real, inverted and of the same size as that of the object. The position of the object should be-

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Answered by abhimalviya121

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The Image Formed by a Concave Mirror is Real, Inverted and of the Same Size as the Object. the Position of the Object Must Then Be: (A) at the Focus (B) Between the Centre of Curvature and Focus (C) at the Centre of Curvature (D) Beyond the Centre of Curvature Concept: Mirror Formula and Magnificent

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Answered by Mysteryboy01

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If the image formed by a concave mirror is real, inverted and of the same size as object then the position of the object must be at the center of curvature.

$<!DOCTYPE html> <html> <svg width="100%" height="300px">\ \textless \ br /\ \textgreater \ <g id="R1" transform="translate(250 250)"> \ \textless \ br /\ \textgreater \ <ellipse rx="100" ry="0" opacity=".3">\ \textless \ br /\ \textgreater \ <animateTransform attributeName="transform" type="rotate" dur="7s" from="0" to="360" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="cx" dur="8s" values="-20; 220; -20" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ <animate attributeName="ry" dur="3s" values="10; 60; 10" repeatCount="indefinite" />\ \textless \ br /\ \textgreater \ </ellipse>\ \textless \ br /\ \textgreater \ </g><use xlink:href="#R1" transform="rotate(72 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(144 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(216 390 150)" />\ \textless \ br /\ \textgreater \ <use xlink:href="#R1" transform="rotate(288 390 150)" />\ \textless \ br /\ \textgreater \ </svg></body></html>$

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The image formed by concave mirror is real, inverted and of the same size as that of the object. The position of the object should be-​

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The image formed by concave mirror is real, inverted and of the same size as that of the object. The position of the object should be-