the image formed by objective lens of a compound microscope is
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Focal length of the objective lens (f1) = 2.0 cm
Focal length of the eyepiece (f2) = 6.25 cm
Distance between the objective lens and the eyepiece (d)= 15 cm
(a) Least distance of distinct vision, (d1) = 25 cm
Therefore, Image distance for the eyepiece (v2) = – 25 cm
Object distance for the eyepiece = u2
According to the lens formula,
1/ v2 - 1/u2 = 1/ f2
1/u2 = 1/ v2 -1/ f2 = 1/-25 - 1/6.25 = -1-4/ 25 = -5/25
u2 = -5 cm
Image distance for the objective lens, (v1) =- d + u2 = 15-5 = 10 cm
Object distance for the objective lens = u2
According to the lens formula,
1/ v1 - 1/u1 = 1/f1
1/u1 = 1/ v1 - 1/f1
= 1/10 - 1/2 = 1-5/10 = -4/10
u1 = -2.5 cm
Magnitude of the object distance (u1) = 2.5 cm
Focal length of the eyepiece (f2) = 6.25 cm
Distance between the objective lens and the eyepiece (d)= 15 cm
(a) Least distance of distinct vision, (d1) = 25 cm
Therefore, Image distance for the eyepiece (v2) = – 25 cm
Object distance for the eyepiece = u2
According to the lens formula,
1/ v2 - 1/u2 = 1/ f2
1/u2 = 1/ v2 -1/ f2 = 1/-25 - 1/6.25 = -1-4/ 25 = -5/25
u2 = -5 cm
Image distance for the objective lens, (v1) =- d + u2 = 15-5 = 10 cm
Object distance for the objective lens = u2
According to the lens formula,
1/ v1 - 1/u1 = 1/f1
1/u1 = 1/ v1 - 1/f1
= 1/10 - 1/2 = 1-5/10 = -4/10
u1 = -2.5 cm
Magnitude of the object distance (u1) = 2.5 cm
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