Question

the image has the question​

Answer 1

Answer:

20 cm^2

Question: In the diagram the area of the smaller square is 10 cm². Find the area of the larger square.

Step-by-step explanation:

Based on assumption: all ard co-centric.

Here,

From one observation:

Diagonal of smaller square = diameter of circle

From other,

Diameter of circle = side of larger square.

Result: Diagonal of smaller square = side of larger square.

Area of smaller square = 10cm²

=> side² = 10 cm² (of smaller)

=> side = √10 cm. So,

diagonal is side√2 = √10*√2 = √20 cm

Therefore, for larger square :

Side of larger square = √20 cm

And, area = side^2 = (√20 cm)^2 = 20 cm^2

Answer 2

Answer:

Area of Larger square is 20cm²

Step-by-step explanation:

Given:

Area of smaller Square = 20cm²

Now to remove diagonal of smaller square we will use below formula.

Area of smaller circle = ½ diagnol²

diagonal²= 10 ×2

diagonal = 10 x 2 diagonal? = 20

$diagnol = \sqrt{20 \: } = \sqrt{4 \times 5} = \sqrt{ {2}^{2} \times 5} = 2\sqrt{5}$

Now diagonal of smaller square = diameter of circle

$= 2\sqrt{5} \: cm$

Also diameter of circle = side of larger square =

$2 \sqrt{5} cm$

hence area of larger square = side²=

$2 \sqrt{5}$

= 20 cm

Area of Larger square is 20cm.