Question

The image is formed by a diverging lens of focal length f. The size of image is one fourth to that of real object. Find the distance of object from the lens?

A) f
B) 2f
C) 3f
D) 4f​

Answer 1

Answer:

Correct option is

D

4.4cm

Concave lens forms the virtual image of a real object. So, let

u=−4x and v=−x

Then, 3x=10 cm

or x=

3

10

cm

∴u=−

3

40

cm and v=−

3

10

cm

Substituting in

f

1

=

10

−3

+

40

3

or f=−

9

40

or f=−4.4 cm.

hope this is help you friend☺

Answer 2

Answer:

Concept:

The event will showcase a curated line-up of established and rising creatives, offering buyers the best in handcrafted goods, including elegant homewares, breathtaking lifestyle products, and delectable cuisine. Distance is a numerical representation of the distance between two objects or points. A physical length or an approximation based on other physics or common usage criteria might be referred to as distance (e.g. "two counties over"). The distance between two points A and B is sometimes written as.

Given:

Focal length $f$

Image size = $1/4th$ of the size of the object

Find:

Find the distance of the object from the lens.​

Answer:

The length of a line segment is the distance between two locations. Congruent segments are those that have the same length. By drawing a line with a ruler, we may compute the distance between two points. On a horizontal and vertical scale, calculate the distance between the points. To calculate the vertical distance, subtract $y2 - y1$. The horizontal distance is then calculated by subtracting $x2 - x1$. Don't be concerned if the subtraction produces negative results.

$m = 1/4$

$m = v/u$

$v/u = 1/4$

$v = u/4$

$1/f = 1/v + 1/u$

$1/f = 4/u + 1/u$

$1/f = 5/u$

$f = u/5$

$u = 5f$