The image of a candle flame formed by a lens is obtained on the screen placed on the other side of the lens. if the image is 3 times the size of the flame and the distance between lens and image is 80cm, at which distance should the candle be placed from the lens? what is the nature of the image and find the focal length of the lens??
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v/u=3
v/80=3
v=240
1/v-1/u =1/f
1/-240 - 1/-80 = 1/f
f=-60
v/80=3
v=240
1/v-1/u =1/f
1/-240 - 1/-80 = 1/f
f=-60
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