The image of a candle flame placed at a distance of 30 cm from a mirror is formed on a screen placed in front of mirror at a distance of 60 cm from its pole. What is the nature of the mirror. Find its focal length. If the height of flame is 2.4 cm , find te height of image.
Answers
Answer:
Explanation:
Given :-
u = - 30 cm
v = 60 cm
h = 2.4 cm
Solution :-
Using mirror formula,
1/f = 1/v - 1/u
⇒ 1/f = 1/60 - (1/- 30)
⇒ 1/f = 1/60 + 1/30
⇒ 1/f = 3/60
⇒ 1/f = 1/20
⇒ f = 20 cm
Magnification, M = v/u = Height of image/height of object
⇒ v/u = 60/-30
⇒ v/u = h'/2.4
⇒ h' = - 60/30 × 2.4
⇒ h' = - 4.8 cm
Hence, The required height of the image is - 4.8 cm
The image formed by the mirror is inverted.
Answer:
Given:
u = - 30 cm
v = 60 cm
h = 2.4 cm
Solution:-
Using mirror formula,
1/f = 1/v - 1/u
⇒ 1/f = 1/60 - (1/- 30)
⇒ 1/f = 1/60 + 1/30
⇒ 1/f = 3/60
⇒ 1/f = 1/20
⇒ f = 20 cm
Magnification, M = v/u = Height of image/height of object
⇒ v/u = 60/-30
⇒ v/u = h'/2.4
⇒ h' = - 60/30 × 2.4
⇒ h' = - 4.8 cm
Hence, The required height of the image is - 4.8 cm
The image formed by the mirror is inverted.