Science, asked by anandita2813, 1 year ago

The image of a candle flame placed at a distance of 30 cm from a mirror is formed on a screen placed in front of mirror at a distance of 60 cm from its pole. What is the nature of the mirror. Find its focal length. If the height of flame is 2.4 cm , find te height of image.


drknaveenraj: SORRY I UNKNOWNLY COPIED THE QUESTION IN THE ANS BOX
anandita2813: I will report it
anandita2813: and then u can answer again if u want

Answers

Answered by VishalSharma01
360

Answer:

Explanation:

Given :-

u = - 30 cm

v = 60 cm

h = 2.4 cm

Solution :-

Using mirror formula,

1/f = 1/v - 1/u

⇒ 1/f = 1/60 - (1/- 30)

⇒ 1/f  = 1/60 + 1/30

⇒ 1/f = 3/60

⇒ 1/f = 1/20

f = 20 cm

Magnification, M = v/u = Height of image/height of object

⇒ v/u = 60/-30

⇒ v/u = h'/2.4

⇒ h' = - 60/30 × 2.4

h' = - 4.8 cm

Hence, The required height of the image is - 4.8 cm

The image formed by the mirror is inverted.

Answered by hansikaballa
18

Answer:

Given:

u = - 30 cm

v = 60 cm

h = 2.4 cm

Solution:-

Using mirror formula,

1/f = 1/v - 1/u

⇒ 1/f = 1/60 - (1/- 30)

⇒ 1/f  = 1/60 + 1/30

⇒ 1/f = 3/60

⇒ 1/f = 1/20

⇒ f = 20 cm

Magnification, M = v/u = Height of image/height of object

⇒ v/u = 60/-30

⇒ v/u = h'/2.4

⇒ h' = - 60/30 × 2.4

⇒ h' = - 4.8 cm

Hence, The required height of the image is - 4.8 cm

The image formed by the mirror is inverted.

Similar questions