The image of an object formed by a mirror is real, inverted and is of magnification-1. If the image is at distance of 30cm from mirror, where is the object placed? Find the position of the image if the object is now moved 20 cm towards the mirror. What is the nature of the image obtained? Justify your answer with the help of a ray diagram.
Answers
Answered by
1
Answer:
I hope it will help you
Explanation:
it is. magnified,real,inverted
Attachments:
Answered by
2
Answer:
+ 30 cm
Explanation:
Given :
Magnification = - 1
Image distance = 30 cm
We know
m = - v / u
- 1 = 30 / u
u = - 30 cm
Now we have ,
1 / f = 1 / v + 1 / u
1 / f = 1 / - 30 - 1 / 30
f = - 15 cm
When object moved 20 cm
u' = - 30 + 20 = - 10 cm
We have f = - 15 cm
We have to find new image distance v'
Again ,
1 / f = 1 / v' + 1 / u'
- 1 / 15 = 1 / v' - 1 / 10
1 / v' = 1 / 30
v' = 30.
Nature of image as :
Virtual
Erect
Magnified.
Attachments:
Similar questions
Math,
5 months ago
Physics,
5 months ago
Political Science,
5 months ago
Chemistry,
9 months ago
Environmental Sciences,
9 months ago
Biology,
11 months ago
Psychology,
11 months ago