Physics, asked by aasthaverma0000, 1 year ago

The image of an object formed by a mirror is real, inverted and is of magnification -1. If the image is at the distance

of 30 cm from the mirror, where is the object placed? Find the position of the image if the object is now moved 20 cm

towards the mirror. What is the nature of the image obtained? Justify your answer with the help of ray diagram​

Answers

Answered by Aishwarya00001
6

Please find the answer in the attachment.

Attachments:
Answered by BendingReality
1

Answer:

+ 30 cm

Explanation:

Given :

Magnification = - 1

Image distance = 30 cm

We know

m = - v / u

- 1 = 30 / u

u = - 30 cm

Now we have ,

1 / f = 1 / v + 1 / u

1 /  f = 1 / - 30 - 1 / 30

f = - 15 cm

When object moved 20 cm

u' = - 30 + 20 = - 10 cm

We have f = - 15 cm

We have to find new image distance v'

Again ,

1 / f = 1 / v' + 1 / u'

- 1 / 15 = 1 / v' - 1 / 10

1 / v' = 1 / 30

v' = 30.

Nature of image as :

Virtual

Erect

Magnified.

Attachments:
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