Science, asked by coolkshitij4717, 1 year ago

The image of an object formed by mirror is real and inverted snd of magnification-1if the image at the distance objective of objective is 30 cm from the near where is object placed find the position of the image if the object is now moved 20cm towards the mirror what is the nature of the image obtained justify with the ray diagram

Answers

Answered by Anonymous
2
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thnku
Answered by BendingReality
6

Answer:

+ 30 cm

Explanation:

Given :

Magnification = - 1

Image distance = 30 cm

We know

m = - v / u

- 1 = 30 / u

u = - 30 cm

Now we have ,

1 / f = 1 / v + 1 / u

1 /  f = 1 / - 30 - 1 / 30

f = - 15 cm

When object moved 20 cm

u' = - 30 + 20 = - 10 cm

We have f = - 15 cm

We have to find new image distance v'

Again ,

1 / f = 1 / v' + 1 / u'

- 1 / 15 = 1 / v' - 1 / 10

1 / v' = 1 / 30

v' = 30.

Nature of image as :

Virtual

Erect

Magnified.

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