the image of an object in a concave mirror is twice the size of the object the distance between the object and the image is 15cm the focal length of the mirror is
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for real image ,
Let u=-x, thenv=-2x
∴ Solving, we get x=30cm, For virtual image , Let u=-x, then y=+2x
∴ Solving, we getx=30cm
For virtual image,
Let u=-x, then v=+2x
∴(12x)+(1-x)=(1-20)
or, x=10cm.
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