Question

The image of an object in a convex mirror is 4 cm from the mirror....radius of curvature is 24 cm find the object position and magnification....

EXPLANATION IS REQUIRED..........

Answer 1

Answer:

Given –

• Image Distance = 4 cm.
• Radius of curvature = 24 cm.
• Focal length = 12 cm.

To Find –

• Object Distance.
• Magnification.

Solution –

Mirror formula : 1/v + 1/v = 1/f

Substituting the values,

➸ 1/4 + 1/u = 1/12

➸ 1/u = 1/12 - 1/4

➸ 1/u = (4 - 12)/48

➸ 1/u = -8/48

➸ 1/u = -4/24

➸ 1/u = -1/6

➸ u = -6 cm

Hence, object distance is -6 cm.

We know, Magnification = -v/u.

Hence, M = -(4/-6)

➸ M = 4/6

➸ M = 2/3

➸ M = 0.6

Answer 2

Answer:

Explanation:

Given :-

Image Distance, v = 4 cm.

Radius of curvature, = 24 cm.

Focal length, f = 24/2 = 12 cm.

To Find :-

Object Distance, u = ??

Magnification, m = ??

Formula to be used :-

Mirror formula i.e 1/v + 1/v = 1/f

Magnification, m = - v/u = h'/h

Solution :-

Putting all the values, we get

Substituting the values,

1/4 + 1/u = 1/f

⇒ 1/u = 1/12 - 1/4

⇒ 1/u = (4 - 12)/48

⇒ 1/u = - 8/48

⇒ 1/u = - 4/24

⇒ 1/u = - 1/6

⇒ u = - 6 cm

Hence, object distance is 6 cm.

Now, Magnification, m = - v/u.

⇒ m = - (4/- 6)

⇒ m = 4/6

⇒ m = 2/3

⇒ m = 0.6

Hence, the magnification is 0.6.