The image of an object is at 10 cm from the con cave mirror if focal length of mirror is 15 cm then find the distance of object from mirror
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1
Answer:
first at concave mirror
u= -15u=−15 ; f= -10f=−10
\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}
v
1
+
u
1
=
f
1
\dfrac{1}{v}-\dfrac{1}{15}= -\dfrac{1}{10}
v
1
−
15
1
=−
10
1
v= -30v=−30
then at convex mirror
u= -10u=−10 ; f= +15f=+15]
\dfrac{1}{v}+\dfrac{1}{u}=\dfrac{1}{f}
v
1
+
u
1
=
f
1
\dfrac{1}{v}-\dfrac{1}{10}=\dfrac{1}{15}
v
1
−
10
1
=
15
1
v= 6v=6
i.e, image is formed at a distance 6cm6cm behind the mirror and it is virtual
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