the image of an object placed at 60 cm infront of a lens is obtained on a screen at a distance of 120 cm from it .Find the focal length of the lens .What would be the height of the image when the object is 3 cm high
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Answer:
10cm
Explanation:
Object distance u = -60 cm
Image distance v = +120 cm
Using lens formula, 1/f = 1/v - 1/u
1/f = 1/120 - ( -1/60 ) = 1/120 + 1/60 = 3/120 = 40
f = +40 cm
H(image) / H(object) = v/u
Hi = -120/60 X 5 = -10 cm :)
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