the image of an object placed at 60cm in front of a lens is obtained on a screen at a distance of 120cm from it. find the focal lenght of the lens . what would be the height of the image if the height of the object is 5cm?
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Answered by
443
hii mate!!
Object distance u = -60 cm
Image distance v = +120 cm
Using lens formula, 1/f = 1/v - 1/u
1/f = 1/120 - ( -1/60 ) = 1/120 + 1/60 = 3/120 = 40
f = +40 cm
H(image) / H(object) = v/u
Hi = -120/60 X 5 = -10 cm :)
hope it helps ☺☺☺☺
Object distance u = -60 cm
Image distance v = +120 cm
Using lens formula, 1/f = 1/v - 1/u
1/f = 1/120 - ( -1/60 ) = 1/120 + 1/60 = 3/120 = 40
f = +40 cm
H(image) / H(object) = v/u
Hi = -120/60 X 5 = -10 cm :)
hope it helps ☺☺☺☺
Answered by
66
Object distance u = -60 cm
Image distance v = +120 cm
Lens formula, 1/f = 1/v - 1/u
1/f = 1/120 - ( -1/60 ) = 1/120 + 1/60 = 3/120 = 40
f = +40 cm
H(image) / H(object) = v/u
Hi = -120/60 X 5 = -10 cm
Good Luck !!!
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