Social Sciences, asked by asdfqwert9556, 9 months ago

The image of an object placed at a distance of 30 cm on the principal axis of a concave mirror from its pole, is formed on the object itself. Find (a) the focal length and (b) linear magnification of mirror.

Answers

Answered by ombaghel334
13

Answer:

given u=-30

a/c to que.

(i) image formed at object so, object kept at centre of curvature

therefore, f=-30/2=-15cm

(ii) as image formed at center of curvature so height of the image= height of obj.

m= -h2/h1=-v/u

m=-30/30=-1

-ve sign shows that image is inverted

Answered by Anonymous
59

Answer:

The minimum distance of the object and its real image from a concave mirror is zero and this occurs when the distance between the object and the mirror is equal to twice the focal length.

Explanation:

The Lens/Mirror formula is

1/u + 1/v = 1/f

u = +15 and f = +10 (both Real distances, hence +)

1/15 + 1/v = 1/10

1/v = 1/10 - 1/15 = 6/60 - 4/60 = 2/60 = 1/30

v = +30

so a real image 30cm from the mirror.

M = v/u = +2 so the image is twice the size of the object. M>0 so inverted.

Similar questions