Math, asked by dd208483, 8 months ago

The image of an objectis is formed on the object
itself placed at 36cm from the pole on the principal axis of concave mirror. calculate the focal length of the mirror and linear magnification​

Answers

Answered by LEGEND778
9

Answer:

Step-by-step explanation:

In case of a concave mirror,

When the object is at the centre of curvature the image is also at the centre of curvature. So Radius of curvature (R) =36 cm

N focal length is half of radius of curvature. Therfore f=18 cm

U=30cm (negative)

V=30 cm (negative)

Linear Magnification =-v/u = - (-36)/(-36)=-1

Answered by Prabal0807
7

Answer:

Focal length (f) will be just half of the given distance of object and image from the pole on the principal axis.

Step-by-step explanation:

As we know,

In a concave mirror, when an image is formed just below the object i.e., then the position of object is at the centre of curvature (C).

It is given that distance from the pole to the object and image is same i.e.,

v = u = 36cm

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