The image of origin about the line 3x + 5y = 17 is
(1) (3,5)
(2) (-2,8)
(3) (2, 28/5)
(4) (4, 22/5)
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Given equation of circle:-
x2+y2+4x+6y+9=0
Given equation of line:-
3x+5y+17=0.....(1)
Let P(a,b) be the pole of line 3xx+5y+17=0 w.r.t. the circle x2+y2+4x+6y+9=0
Now equation of polar of point P(a,b) w.r.t. the circle x2+y2+4x+6y+9=0-
ax+by+2(x+a)+3(y+b)+9=0
⇒(a+2)x+(b+3)y+(2a+3b+9)=0.....(2)
As the equation (2)&(3) are same, therefore,
3a+2=5b+3=172a+3b+9
Now,
Case I:-
3a+2=5b+3
⇒5(a+2)=3(b+3)
⇒5a
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