Question

The image of point P( 4,  - 7) in x -axis is
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Answer 1

Step-by-step explanation:

Let P(α,β,γ) be the image of the point Q(3,5,7), so midpoint of PQ lie on the given plane.

⇒2(2α+3)+(2β+5)+(2γ+7)=0

∴2α+β+γ+18=0:...(i)

Also PQ is perpendicular to the normal to the plane,  

⇒2α−3=1β−5=1γ−7...(ii)

Solving  (i) and (ii), we get

 α=−9,β=−1,γ=1.

Therefore, image is (−9,−1,1).