Question

the image of the point (2,7) with respect to line y=x as line of symmmetry

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Answer 1

Answer:

Let A=(2,1) & A′=(5,2)

∴The line is mirror.

∴ Line is perpendicular to AA′ and passes through the midpoint.

Slope of AA′=31

∴ Slope of mirror=−3

∴ Equation =(y−23)=−3(x−27)

⇒y−23=−3x+221

⇒2y−3=−6x+21

⇒6x+2y−24=0

⇒3x+y−12=0

Explanation:

I hope This Is Helpful For You ✌

Answer 2

Answer:

Symmetry can be useful in graphing an equation since it says that if we know one portion of the graph then we will also know the remaining (and symmetric) portion of the graph as well. We used this fact when we were graphing parabolas to get an extra point of some of the graphs.

Symmetry can be useful in graphing an equation since it says that if we know one portion of the graph then we will also know the remaining (and symmetric) portion of the graph as well. We used this fact when we were graphing parabolas to get an extra point of some of the graphs.In this section we want to look at three types of symmetry.