Question

the imaginary part of function tan (x+iy) is value​

Answer 1

This is where I'm at:

I know

cos(z)=eiz+e−iz2,sin(z)=eiz−e−iz2i,

where

tan(z)=sin(z)cos(z).

Applying the above, with a little manipulation, gives me:

tan(z)=i(e−iz−eiz)eiz+e−iz.

Answer 2

Step-by-step explanation:

the imaginary part of function tan (x+iy) is value