Question

The impedance of L-R series connection is
(A) R2+w212
(B) R+ WL
(C)
R+WL
(D)
VR2 +w212​

Answer 1

Answer:

A is the correct answer

Answer 2

To find:

Impedance of a L-R series combination.

Calculation:

Let us consider that a circuit contains an inductor L and a resistor R connected in series combination to an alternating voltage of frequency $\omega$.

So, inductive reactance :

$\therefore \: X_{L} = \omega L$

And resistance is R .

So, let impedance be Z :

$\therefore \: Z = \sqrt{ {(X_{L})}^{2} + {(R)}^{2} }$

$= > \: Z = \sqrt{ {( \omega{L})}^{2} + {(R)}^{2} }$

$= > \: Z = \sqrt{ { \omega}^{2} {L}^{2} + {R}^{2} }$

So, final answer is:

$\boxed{ \bold{ \large{\: Z = \sqrt{ { \omega}^{2} {L}^{2} + {R}^{2} }}}}$