the improper integral of limit o to 1.. dx/square root (1- x^3) i
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Answer:
Answered by
0
Answer:
1
Step-by-step explanation:
Explanation:
Making
x
=
sin
y
with
d
x
=
cos
y
d
y
and substituting into the integral
I
=
∫
x
d
x
√
1
−
x
2
≡
∫
(
sin
y
cos
y
)
cos
y
d
y
=
∫
sin
y
d
y
=
−
cos
y
The integration limits are changed to
x
=
0
→
y
=
0
x
=
1
→
y
→
π
2
so
I
=
−
cos
(
π
2
)
−
(
−
cos
(
0
)
)
=
1
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