The improvement of a cloud from a point above a meter h of a lake is a & the deterioration of its reflection on a lake is a b. Prove that the distance of the cloud from the point at which the cloud is seen is 2hsec a / (tan b - tan a)
Answers
Step-by-step explanation:
Distance of the cloud from the point of observation = 2hSecα/(Tanβ - Tanα)
Step-by-step explanation:
Let sat Height of Cloud from point of observation = C
Height of cloud from Lake = C + h
Depth of Cloud reflection from point of observation = C + h + h = C + 2h
Horizontal Distance of cloud from point of observation = B
Tanα = C/B
=> C = BTanα
Tanβ = (C + 2 h)/B
=> C = BTanβ - 2 h
BTanα = BTanβ - 2 h
=> 2h = BTanβ - BTanα
=> 2h = B(Tanβ - Tanα)
=> B = 2h/(Tanβ - Tanα)
Cosα = B/distance of the cloud from the point of observation
=> distance of the cloud from the point of observation = B/Cosα
= BSecα
= 2hSecα/(Tanβ - Tanα)
distance of the cloud from the point of observation = 2hSecα/(Tanβ - Tanα)
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Answer:
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