Question

The impulse on a body at rest when acted upon by a force of 8N for 0.2sec​

Answer 1

Answer:

Impulse on the body would be J−FΔt, where F=20N,t=3s also impulse is change in momentum :J=MΔV

so,

m(v−u)=Ft,m−4kg,u=0m/s gives,

4V=20×3→V=15m/s