Question

the in-centre of the triangle with vertices (0,0),(1,0),(0,1) is .............give reson

Answer 1

Answer:it is a right angle triangle

Step-by-step explanation:

Answer 2

Answer:

$(2 - \sqrt{2} \div 2$

$2 - \sqrt{2 \div 2)}$

Step-by-step explanation:

incentre of the triangle

The points form a right angled triangle

a=1, b=^2, c=1

(x1, y1)=(0, 1), (x2, y2)=(0, 0), (x3, y3)=(1, 0)

=( ax1+bx2+cx3/a+b+c, ay1+by2+cy3/a+b+c)

=(0+0+1/2+^2, 1+0+0/2+^2)

=(1/2+^2, 1/2+^2)

on taking LCM

we get,,

= (2-^2/2, 2-^2/2)

hope so u understood !!!