Question

the
In the given figure, if ZAOC + ZBOD = 266°, find all the fou
133
LA0CE2A0D 470
A
$260°C
А
KD.
Fig. Q. 12​

Answer 1

Step-by-step explanation:

Given that,

∠AOC+∠BOD=266

0

But In the figure

∠AOC=∠BOD (Vertically opposite angle)

Then, ∠AOC=∠BOD=dfarc266

0

2=133

0

Now,

∠AOC+∠AOD=180

0

∠AOD=180

0

−133

0

∠AOD=47

0

And,∠AOD=∠BOC=47

0

Hence, ∠AOC=133

0

,∠AOD=47

0

,∠BOD=133

0

and∠BOC=