The incentre of the triangle formed by the lines x + y = 1, x=1, y=1 is (I, m) then l^2 + m²
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Answer:
⇒(1−b)=(1−a)=
∣
∣
∣
∣
2
a+b−1
∣
∣
∣
∣
⇒(a−1)
2
=(b−1)
2
⇒a=b
⇒1−a=
2
2a−1
⇒2a−1=
2
−
2
a
⇒a=
2
(
2
+1)
2
+1
=
2
1
Step-by-step explanation:
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