Question

.The incircle of ∆ABC touches BC, CA and AB at D, E, F respectively. If

AB = AC, show that BD = BC.​

Answer 1

Answer:

Fig. the incircle of △ABC, touches the sides BC, CA and AB at D, E respectively. Show that :

AF + BD + CE = AE + BF + CD = ½ (Perimeter of △ABC).

plz mark as brainliest , follow me and thanks me