Question

The Incircle Of Triangle ABC with sides ab=12cm bc=16cm and ca=8cm touches at D,E and F Respectively Find AD BE And CF​

Answer 1

Answer:

We know that AD= AF

                         BD=BE

                          CE=CF

Let AD= AF=x

 BD=BE=y

CE=CF=z

Then x+y=12

y+z=8

x+z=10

On Solving above equation we get x=7,y=5,z=3

So AD=7 , BE=5 , CF= 3

Step-by-step explanation:

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Answer 2

Answer:

We know that AD= AF

BD=BE

CE=CF

Let AD= AF=x

BD=BE=y

CE=CF=z

Then x+y=12

y+z=8

x+z=10

On Solving above equation we get x=7,y=5,z=3

So AD=7 , BE=5 , CF= 3