The income of A and B are in the ratio of 3:4 and their expenditures are in the ratio of 5:7. If each saves Rs 1000, find their incomes
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Let income of A and B be 3x and 2x respectively. Also, their expenditure is 5y and 3y.
Now, according to question,
3x - 5y = 1000 ------- (i) × 3
2x - 3y = 1000 ---------- (ii) × 5
9x - 15y - 10x + 15y = 3000 - 5000
Or, -x = -2000
Or, x = 2000
Then, income of A = 3x = 3 × 2000 = Rs. 6000
ATQ:
The income of A & B is in the ratio 3:4.
A's Income ➞ 3x.
B's Income ➞ 4x.
The expenditure of A & B is in the ratio 5:7.
A's Expenditure ➞ 5y
B's Expenditure ➞ 7y
Both of their savings is Rs. 1000.
We know that:
∴ A's savings will be:
➞ A's Income - A's Expenditure = A's Savings
➞ 3x - 5y = 1000 ⇔ Eq(1)
∴ B's savings will be:
➞ B's Income - B's Expenditure = B's Savings
➞ 4x - 7y = 1000 ⇔ Eq(2)
Eq(1) × 4 ⇒ 12x - 20y = 4000 ⇔ Eq(3)
Eq(2) × 3 ⇒ 12x - 21y = 3000 ⇔ Eq(4)
Subtract Eq(3) from Eq(4):
➞ 12x - 21y - (12x - 20y) = 3000 - 4000
➞ 12x - 21y - 12x + 20y = -1000
➞ -21y + 20y = -1000
➞ -y = -1000
➞ y = 1000
Substitute the value of y in Eq(3):
➞ 12x - 20y = 4000
➞ 12x - 20(1000) = 4000
➞ 12x - 20000 = 4000
➞ 12x = 4000 + 20000
➞ 12x = 24000
➞ x = 24000/12
➞ x = 2000
Therefore:
A's Income ➞ 3x ➞ 3(2000) ➞ 6000Rs.
B's Income ➞ 4x ➞ 4(2000) ➞ 8000Rs.