The income of A:B:C are in the ratio 3:7:4 and their expenses are in the ratio 4:3:5.if A saves 1/8 of his income. Then find the ratio of savings A:B:C?
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Answer:
12:161:23 IND.
Step-by-step explanation:
A's exp. = 3x - (3x/8) = 21x/8
21x/8 = 4y => y = 21x/32
B's Exp. => 3y = 3(21x/32) = 63x/32
C's Exp.=> 5y = 5(21x/32) = 105x/32
A's savings = 3x/8
B's savings = 7x - (63x/32)= 161x/32
& C's savings = 4x - (105x/32) = 23x/32
savings ratio
A:B:C = 3x/8 : 161x/32 : 23x/32
= 12: 161 : 23
OR
A's Sv. = 1/8 , saving = 1 ,income = 8
exp. = 8-1 = 7
multiple In.by 4 and exp. by 3
A's savings
=(3×4)×8 - (4×3) ×7 = 12
similarly,
B's savings =7×4×8 - 3×3×7
= 161
C's savings = 4×4×8 - 5×3×7
= 23
A:B:C = 12 : 161 : 23
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