Question

the income of a businessman in last 5 years is in the ratio 3:2:6:5:7. if the average of income of last five years is rs.4600. Calculate the income of each year

Answer 1

Answer:

3:2:6:5:7

$3x + 2x + 6x + 5x + 7x = 4600$

$23x = 4600$

$x = \frac{4600}{23}$

$x = 200$

now

3x = 3 × 200 = 600Rs

2x = 2 × 200 = 400Rs

6x = 6 × 200 = 1200Rs

5x = 5 × 200 = 1000Rs

7x = 7 × 200 = 1400Rs

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Answer 2

Given :

• The income of a businessman in last 5 years is in the ratio 3:2:6:5:7.
• The average of income of last five years is ₹ 4600.

To Find :

• The income of each year.

Solution :

Let's Assume,

• The income of first year be 3b
• The income of second year be 2b
• The income of third year be 6b
• The income of fourth year be 5b
• The income of fifth year be 7b

According to the Question :

• 3b + 2b + 6b + 5b + 7b = 4600
• 5b + 11b + 7b = 4600
• 16b + 7b = 4600
• 23b = 4600
• b = 4600/23
• b = ₹ 200

Therefore :

• The income of first year = 3b
• The income of first year = 3 × 200
• The income of first year = ₹ 600

• The income of second year = 2b
• The income of second year = 2 × 200
• The income of second year = ₹ 400

• The income of third year = 6b
• The income of third year = 6 × 200
• The income of third year = ₹ 1200

• The income of fourth year = 5b
• The income of fourth year = 5 × 200
• The income of fourth year = ₹ 1000

• The income of fifth year = 7b
• The income of fifth year = 7 × 200
• The income of fifth year = ₹ 1400

Hence, the income for first , second , third , fourth and fifth year are ₹ 600 , ₹ 400 , ₹ 1200 , ₹1000 , ₹1400 respectively.

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