Question

the income of a businessman in the last 5 years in the ratio of 3:2:6:5:7. If the average income of last 5 year is 4600. calculate the income of each year​

Answer 1

Answer:

Let 5 years income be 3x, 2x, 6x, 5x , 7x .

Then, average income = (3x+ 2x+6x+ 5x + 7x) /5 = 23x / 5

We have, 23 x /5 = 4600

or, 23 x = 4600 * 5

or, x = 4600* 5 / 23

---> x = 200*5 = 1000

Hence 5 year income = 3000, 2000, 6000, 5000, 7000.

Answer 2

Answer:

The income of five last years

3000, 2000, 6000, 5000, 7000.

Step-by-step explanation:

Let the income of last five years be 3x, 2x, 6x, 5x, 7x

The total income of the last five years

= 3x + 2x + 6x + 5x + 7x

They have given that average income of last five years is 4600

4600 =  The total income of the last five years / 5

The total income of the last five years = 4600 × 5

                                                               = 23000

Threfore,

3x + 2x + 6x + 5x + 7x = 23000

(x)(23) = 23000

x = 1000

Therefore the income of the five last years is

3000, 2000, 6000, 5000, 7000.