Math, asked by deependradixit1423, 2 months ago

The income of a company increases 20% per
annum. If its income is F 26,64,000 in the year
2012, then its income in the year 2010 was :​

Answers

Answered by shashank35132
0

Step-by-step explanation:

Let the income of 2010 be " x ".

Hence,

income \: of \: 2011 = x + 20\% \: of \: x \\income \: of \: 2011 = x +  \frac{20x}{100} \\ income \: of \: 2011 =  \frac{100x + 20x}{100}  \\  income \: of \: 2011 =  \frac{120x}{100}  \\  income \: of \: 2011 =  \frac{12x}{10}

Now,

income \: of \: 2012 =  \frac{12x}{10} +  20\% \: of \:  \frac{12x}{10}  \\  income \: of \: 2012 =   \frac{12x}{10} +  \frac{20 \times 12x}{100 \times 10} \\income \: of \: 2012 =  \frac{12x}{10}  +  \frac{6x}{25}   \\ income \: of \: 2012 =  \frac{60x + 12x}{50}  \\  income \: of \: 2012 =  \frac{72x}{50}  \\  income \: of \: 2012 =  \frac{36x}{25}

From the question, we know that income of 2012 = Rs 26,64,000.

Therefore,

\frac{36x}{25}  = rs \: 2664000 \\ x =  \frac{rs \: 2664000 \times 25}{36} = rs \: 1850000

Hence, the income of the company in 2010 was Rs. 18,50,000.

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