Question

The income of a person is Rs.3,00,000 in the first yera and the recieves an increase of Rs.10,000 to his income per year for the next 19 years .Find d the total amount, he RECIEVED in 20 years ?

Answer 1

$\blue{hello}$

$\pink{here \: is \: u \: r \: ans : }$

a=3,00,000
d=10000
n=20
S=n/2{2a+(n-1)d}
S=10*{6,00,000+19*10000}
S=10*790000
S=79,00,000
the money received by person in 20 year is
$\huge \red{7900000}$

$\huge\purple{soni}$

$\huge \blue { ram \: ram }$
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Answer 2

ĀNSWĒR ✍☺


$\bold{Here , we \: have \: an A.P \: with }$

$a =3,00,000 \\ d = 10,000 \\ and \: n = 20 \\ by \: using \\ sn \: formula \\ sn = \frac{n}{2} (2a + (n - 1)d \\ so \\ s20 = \frac{20}{2} (2 \times 3,00,000 + (20 - 1)10,000) \\ = s20 = 10(600000 + 19 \times 10000) \\ = 10(790000) = 79,00,000 \\ \\ hence \: ,the \: person \: recieved \: Rs \: 79,00,000 \: as \: the \: \: total \: amount \: at \: the \: end \: of \: 20years$


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#Nishu HarYanvi ❤