The increase in entropy of 1 kg ice at 200K which is heated to 400 K at constant atmospheric pressure will be
Cp (ice) = 2.09 * 10^3 j/kg degree
Cp (water) = 4.18 * 10^3 j/kg degree
Cp (steam) = 2.09 * 10^3 j/kg degree
Lf(C'273K) = 3.34*10^5 J/kg
Lv(water'273K) = 22.6*10^5 J/kg
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